What is difference b/w ll deno = 1ll and ll deno = 1

#1

Can you tell me the exact difference between ll deno = 1;
and ll deno = 1ll;

#2

The ll makes the integer literal of type long long .

So 1LL , is a 1 of type long long .

Without the , the literal would only be of type int .

#3

Can you give me some example where it will creating the difference

#4

if you have a function which accepts two long long intergers as argument and you pass a long long and a constant number

refer this code : - https://ide.codingblocks.com/s/241610

#5

Sir in the video suppose if we do ll deno = 1; then what is the thing where we got the error; like if i want to store a 9999999999999 in deno it can store this number. Why there is a need to do ll deno = 1ll.

#6

you can do ll deno =1 its all same in case of initialization

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#7

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