#include
using namespace std;
int main() {
int b,c;
char a=‘a’;
while(a!=‘X’||a!=‘x’)
{
cin>>a;
if(a==’+’)
{
cin>>b>>c;
cout<<b+c<<endl;
}
else if(a==’-’)
{
cin>>b>>c;
cout<<b-c<<endl;
}
else if(a==’’)
{
cin>>b>>c;
cout<<bc<<endl;
}
else if(a==’/’)
{
cin>>b>>c;
cout<<b/c<<endl;
}
else if(a==’%’)
{
cin>>b>>c;
cout<<b%c<<endl;
}
else{
cout<<“Invalid operation. Try again.”<<endl;
}
}
return 0;
}
Hello @aviral989,
Please share your code using Online Coding Blocks IDE.
The way you have shared it has introduced many syntax errors to it.
STEPS:
Hello @aviral989,
I apologies for replying this late.
Actually, I was out of Delhi due to some emergency.
I hope, you would understand.
Now, coming back to your doubt.
There are two problems with your code:
You have created an infinite loop.
Solution:
Use logical AND operator instead of a logical OR.
Reason:
The loop should execute only if both conditions are true.
It is printing the statement :
Invalid operation. Try again.
for a=‘x’ and a=‘X’, which is not required
Reason:
while loop
Solution:
Use do-while loop.
Hope, this would help.
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