Two pointer sum approach

#1

Incase of duplicates this two pointer sum approach will fail. So how to do when there are duplicates.

#2

in that case you have to print all possible pairs, like this

#3

I hope I’ve cleared your doubt. I ask you to please rate your experience here
Your feedback is very important. It helps us improve our platform and hence provide you
the learning experience you deserve.

On the off chance, you still have some questions or not find the answers satisfactory, you may reopen
the doubt.