Today daily code byte question that is of three musketers

#1

#include<bits/stdc++.h>
#define ll long long
using namespace std;
int main () {
ll int n;
cin>>n;
int athos=0,porthos=0,aramis=0;
ll int expo=(n-1)/16;
ll int power=pow(2,expo);
ll int a=(n-1)%16;
if(a>=8 && a<16)
aramis=power;
else if(a>=2 && a<8)
porthos=power;
else
athos=power;

cout<<athos<<" "<<porthos<<" "<<aramis;
return 0;

}

#2

@anshuman Could you provide the question. Also please raise doubts in the section in which it is described it helps in faster resolution of doubt

#3

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