TLE in one testcase in Exist OR Not

#1

i submitted this code, its complexity is O(Q) but still getting TLE in one testcase plz see to it

#2

Hi @wadhwasaab, pls add a && q>=0 in line no. 26 of your code. And your code will work fine then.

Also one TIP, instead of using the hashmap like the way u did, what you can do is:

For line 17 - 22, just do:

aval[x] = 1 ;

Now when we will recieve a query we will just chech wether ava[x] is 1 or not and the same will be done as follows for line no. 28. Use the if else as:

if ( val[x]==1 ) cout << “Yes\n” ;
else cout << “No\n” ;

And yeah since Yes and \n both are strings and \n has to appear immediately after Yes or No so you can write them together as i did in above code segment.

Hope this helps :slight_smile:

#3
#4

still getting tle in the same test case as before