step 1: fill 11 min hour glass with hand and immediately transfer to 7 min hour glass .
now 11 min hour glass contains sand approximate to 4 min .
step 2: throw the sand of 7 min hour glass and transfer those equivalent 4 min sand to 7 min hour glass.
step 3: fill 11 min hour glass again and let it get emptied and once it get empties , immediately start 7 min hour glass which contains sand of equivalent 4 min ( transferred from 11 min hour glass) .
There is a much optimised solution to this
Is my solution correct ?
how you can say it reserves memory statically , we are providing “n” a runtime only. so obviously it is done dynamically
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