Test case 2 fail

#1

#include
using namespace std;
int main()
{
long long int a,b,c;
char ch;

cin>>ch;

while(ch!='x' && ch!='X')
{
    if(ch=='+')
    {
        cin>>a>>b;
        c=a+b;
        cout<<c<<endl;
    }
    else if(ch=='-')
    {
        cin>>a>>b;
        c=a-b;
        cout<<c<<endl;
    }
    else if(ch=='*')
    {
        cin>>a>>b;
        c=a*b;
        cout<<c<<endl;
    }
    else if(ch=='%' && b!=0)
    {
        cin>>a>>b;
        c=a%b;
        cout<<c<<endl;
    }
    else if(ch=='/' && b!=0)
    {
        cin>>a>>b;
        c=a/b;
        cout<<c<<endl;
    }
    else
         cout<<"Invalid operation. Try again."<<endl;
    cin>>ch;
}

return 0;

}

#2

Modified code

Your Mistake
else if(ch==’%’ && b!=0)
you can’t check b before taking input (a and b)
also in the question it is mention that b will never be 0
so just omit this condition

#3

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