Test Case 1 is unable to pass

#1

I am unable to figure out why test case 1 is not passing.

def check_sort(count, input_string):
if (count != len(input_string)):
return False

if (count <= 0 or count >= 1000):
    return False

if (len(input_string) == 0):
    return False


elif (count == 2):
    return input_string[0] < input_string[1]

return input_string[0] < input_string[1] and check_sort(count - 1, input_string[1:])

number = int(input())
input_list = list(map(int, input().strip().split()))[:number]
print(check_sort(number, input_list))

#2

You can simply write a function which takes in two parameters - array and its size
Now we have to figure out the base cases -

  1. If size=1 or size=0 at any point, we return true as an array of size 0 or 1 will be sorted.
  2. Comparing last and second last elements - if arr[n-1] < arr[n-2], we return false.
    And finally the recurrence relation will be -
    return function(arr, n-1)
#3

@amanindersingh Please mark your doubt as resolved if you are satisfied.

#4

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