Target sum pair(test case 4)

#1

wrong answer in test case 4
code:-

#include
using namespace std;

int main()
{
int N, target,sum=0,a[1000];
cin >> N;

for (int i = 0; i < N; i++)
	cin >> a[i];

cin >> target;

for (int i = 0; i < N ; i++)
{
	for (int j = i; j < N; j++)
	{
		sum = a[i] + a[j];

		if (sum == target) 
		{
			if (a[i] < a[j])
				cout << a[i] << " and " << a[j];
			else
				cout << a[j] << " and " << a[i];
		}
		sum = 0;
	}
	cout << endl;
}
return 0;

}

please tell me where to make the correction.

#2

hey @S19LPN0126, just start inner for loop from i+1. here is your updated code https://ide.codingblocks.com/s/109093

1 Like
#3

hey @S19LPN0126 , if your query is resolved. Please mark this doubt as resolved and rate me on the basis of your experience.
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#4
#5

hey @S19LPN0126, are you facing any problem with this code.

#6

no , they temporarily blocked me from replying.
i got the code, j=i is reading the same number twice.
thanks by the way :slight_smile:

#7

hey @S19LPN0126, if you have no query now, please mark this doubt as resolved.