Taking integer input after getline

#1

I am unable to take integer input after using getline to input the string… i tried cin.ignore() but that is not working . Can you suggest something ?

#2

Sure @raks1234,

Please, share the code that is causing issue.

#3 
 #include<iostream>
#include<algorithm>
#include <vector>
#include <string>
using namespace std;
bool compare(pair<string,int>p1,pair<string,int>p2)
{
	if(p1.second==p2.second) return p1.first<p2.first;
	return p1.second>p2.second;
}
int main() {
	vector<pair<string,int>> v;
	int x,N;
	cin>>x>>N;
	cin.get();
	while(N>0)
	{
		string s;
		int sal;
		getline(cin,s);
		cin.ignore(sal,'\n');
		cout<<sal;
		if(x<=sal)
		{
			v.push_back(make_pair(s,sal));
		}
		
		N--;
	}
	sort(v.begin(),v.end(),compare);
	for(auto i: v)
	{
		cout<<i.first<<" "<<i.second<<endl;
	}

	return 0;
}
#4

Hello @raks1234,

Try to use the following statement:
getline(cin,s);
cin.get();
cin>>sal;

instead of:
getline(cin,s);
cin.ignore(sal,’\n’);

Let me know if this works.

#5

Doesn’t seem to work.

#6

Anyway, I figured out that using cin to take string input works in this case, however still have a doubt that why getline() doesn’t work even though we are using cin.get() or cin.ignore()

#7

Hello @raks1234,

The following will surely work:
getline(cin,s,’ ');
cin>>sal;

The reason why what i have suggested previously was not working:
As the string and the integer were separated by a white space not endline character.
And getline reads white space also.
So, s was reading sara 100 as a single string.

Above i have specified the delimiter as white space.
Thus, it will work.

1 Like
#8

Yes, it worked. Thanks for your help.

#9

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