Sum of two arrays

#1

why this is producing wrong output

#2

Bro the logic you have used is not correct, let me help you in building it
Suppose you have input like this:

5
9 9 9 9 9
5
9 9 9 9 9

How will you approach this problem?
We have to do this question in such a manner that every cell of an array doesn’t go beyond number 9, if you will do so you will see
Cell 1 from right 9+9 = 18, 8 in cell . One in carry.
Cell 2 from right 1+9+9 = 19, 9 in cell . One in carry.
Cell 3 from right 1+9+9 = 19, 9 in cell . One in carry.
Cell 4 from right 1+9+9 = 19, 9 in cell . One in carry.
Cell 5 from right 1+9+9 = 19, 19 in cell . Array index ends.

TIP: Try to start your array traversal from the end of the indexes, it will be easy for you :smile:

#3

actually i wanted to implement same thing but i am not able to write correct form.can u please comment out the error in my code

#4

There are lot’s of mistake in your code, i am writing whole code , with comments. You can refer that.

#5

Take reference from this code

#6


can u please explain from line 18 to 25 logic.
int t=abs(N-M);

int max=(N>M)?N:M;

int temp[max];

for(int i=0; i<max; i++)

{

    if(i<t)

        temp[i]=0;

    else if(N<M)

        temp[i]=a[i-t];

    else if(N>=M)

        temp[i]=b[i-t];

}
#7

it means t has |N-M| i.e, mode of (N-M) positive difference

It means that if N is greater then max has value of N , else if M is greater then max has value of M

let N = 5 & M =3, t = 5-3(2)

so if i<2 temp[0, 2] = 0;

if N<M , it is not true for this case

If N>=M, temp[3, 5] = b[0, 2]

So it means that temp[0, 2] = 0 and temp[3, 5] = b[0, 2]

#8

so this step was implemented soo that in blank spaces no garbage value is added to it except 0.?

#9

Yes , this statement ensures it that there should be no garbage value.

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