Sum of two arrays (two wrong answers)

#1
#2 
import java.util.*;
public class Main {
    public static void main (String args[]) {
        Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int arr1[] = new int[n];
		for (int i = 0; i < arr1.length; i++) {
			arr1[i] = sc.nextInt();

		}

		int m = sc.nextInt();
		int arr2[] = new int[m];

		for (int j = 0; j < arr2.length; j++) {
			arr2[j] = sc.nextInt();

		}
        
		if(n>m) {
			sum(arr1,arr2,n,m);
		}else {
			sum(arr2,arr1,m,n);
		}
	}
	
	
	public static void sum(int a[], int []b, int n , int m ) {
		int carry =0,s=0;
		int i=n-1;
		int j=m-1;
		int k=n-1;
		int sum[] = new int[k+1];//you should make an array of k+1 size
		while(j>=0) {
			s=a[i]+b[j]+carry;
			sum[k]=s%10;
			carry = s/10;
			i--;
			j--;
			k--;
		}
		
		while(i>=0) {
			s=a[i]+carry;
			sum[k]=s%10;
			carry=s/10;
			i--;
			k--;
		}
		
		
		if(carry==1) {
			System.out.print(1+", ");//if there is a carry then dont add 10 just print 1 do a dry run for 99 and 999
		}
		for(int r =0;r<n;r++)
		{
			System.out.print(sum[r]+", ");
		}
		System.out.println("END");
    }
}

you do not have to impose conditions on n and m

#3

I hope I’ve cleared your doubt. I ask you to please rate your experience here
Your feedback is very important. It helps us improve our platform and hence provide you
the learning experience you deserve.

On the off chance, you still have some questions or not find the answers satisfactory, you may reopen
the doubt.