Sum of 2 arrays- how do i code for a carry?

#1

code:
include iostream
using namespace std;
int main() {
int n,m,i;
cin>>n;
int arr1[100];
for(i=0;i<n;i++)
cin>>arr1[i];

cin>>m;
int arr2[100];
for(i=0;i<n;i++)
cin>>arr2[i];

int sum[100];
for(i=0;i<n;i++)
{
	sum[i]=arr1[i]+arr2[i];
	cout<<sum[i]<<", ";
}
cout<<"END";
return 0;

}

#2

Hey @vashishthkuntal.gajjar2019
Just add 2 nos
say 99 and 999 on paper and dont do this in mind
You will get ur answer
In case u dont then let me know :slight_smile:

#3

Algorithm:

1.Traverse both the arrays simultaneously from the end until we reach the 0th index of either of the array.
2.While traversing each element of array, add an element from both arrays and carry from the previous sum.
…………2.1 Store the unit digit of the sum(obtained by doing - sum%10) in the ans array.
…………2.2 forward carry(obtained by doing - sum/10) for the next index sum.
3.After the loop ends we are left with one of the arrays and the carry.
4.We will now repeat step 2 but now for one array which is left after the loop.
5.If carry !=0 then store the carry in the 0th index of ans array.
6.Print the ans array .

#4

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