Sum it up problem

#1

My out is almost correct but I am not able to pass the test case

#2

@vivekpatel there should spaces between every no.
o/p for the input testcase is:
1 1 6
1 2 5
1 7
2 6
but your o/p is:
116
125
17
26

#3

Also for input :
4
1 1 2 2
3
your output:
12
12
correct:
1 2

#4

I am not unable to print spaces between them
tell me your approch to solve the problem

#5

You can refer this-


I have removed duplicates at the time i achieved a answer and given space while printing
@vivekpatel

#6

m.find(s)==m.end()
I am unable to under stand this

#7

how and why are you using map

#8

m.find(s)==m.end()
it means s is not present in the map.
i have used map as it it is the property of map
that it remove duplicates automatically

#9

like if u insert in map following numbers
1 2 3 2 1 3 3
map will contain 1 2 3 only

#10

how map can remove 1, 7 and 7 , 1

#11

s is storing 17 for both of them so in map 17 and 17 gets inserted which makes one 17

#12

string 17 and 71 are diffrent

#13

if there is one permutation of 1 , 7 and of 7, 1 then map will treat them same

#14

wait i am implementing it a little simpler will tell you in few mins

#15


here see this i have sorted the initial array so s becomes 17 both times
i hope it now became cleared

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#16

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