Subarray with distinct

#1

NOT ABLE TO CODE CAN I GET CODE OF THIS

#2

Follow this appraoch:

The solution is based on the fact that if we know all elements in a subarray arr[i…j] are distinct, sum of all lengths of distinct element subarrays in this subarray is ((j-i) * (j-i+1))/2 .
How? the possible lengths of subarrays are 1, 2, 3,……, j – i +1. So, the sum will be ((j – i ) * (j – i +1))/2.
We first find largest subarray (with distinct elements) starting from first element. We count sum of lengths in this subarray using above formula. For finding next subarray of the distinct element, we increment starting point, i and ending point, j unless (i+1, j) are distinct. If not possible, then we increment i again and move forward the same way.

#3

If you are still unable to code it, you can have a look at this very easy implementation of this here.

#4

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