Structure identical

#1

i am unable to pass one test case i this,can u help me out.

#2

@guptarahul3100
Please send your code

#3

#include<bits/stdc++.h> using namespace std ; class node { public: int data ; node* left ; node* right ; node(int d){ data = d ; left = NULL ; right = NULL ; } } ; node* build(string r){ if(r == “false”) return NULL ; int d ; cin >> d ; node* root = new node(d) ; string r2 ; cin >> r2 ; root->left = build(r2) ; string r3 ; cin >> r3 ; root->right = build(r3) ; return root ; } bool check(node* root1,node* root2){ if(root1 == NULL && root2 == NULL) return true ; if((root1 != NULL && root2 == NULL ) || (root1 == NULL && root2 != NULL )) return false ; return (check(root1->left,root2->right) && check(root1->right,root2->right)) ; } int main(){ node* root1 = NULL ; node* root2 = NULL ; root1 = build(“true”) ; root2 = build(“true”) ; if(check(root1,root2)) cout << “true” ; else cout << “false” ; }

#4

#include<bits/stdc++.h>
using namespace std ;

class node {
public:
int data ;
node* left ;
node* right ;
node(int d){
data = d ;
left = NULL ;
right = NULL ;

}

} ;

node* build(string r){
if(r == “false”) return NULL ;
int d ;
cin >> d ;
node* root = new node(d) ;
string r2 ;
cin >> r2 ;
root->left = build(r2) ;
string r3 ;
cin >> r3 ;
root->right = build(r3) ;
return root ;
}

bool check(node* root1,node* root2){
if(root1 == NULL && root2 == NULL) return true ;
if((root1 != NULL && root2 == NULL ) || (root1 == NULL && root2 != NULL )) return false ;

return (check(root1->left,root2->right) && check(root1->right,root2->right)) ;

}

int main(){
node* root1 = NULL ;
node* root2 = NULL ;
root1 = build(“true”) ;
root2 = build(“true”) ;
if(check(root1,root2)) cout << “true” ;
else cout << “false” ;
}

#5

@guptarahul3100
Please send it one CB IDE

#6

@guptarahul3100
It was a silly error
You did
check(root1->left,root2->right)
It has to be
check(root1->left,root2->left)

#7

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