How does the inner most loop execute n^2 times?
Find the Complexity of the given snippet.
void function(int n)
{
int count = 0;
for (int i=0; i<n; i++)
for (int j=i; j< i*i; j++)
if (j%i == 0)
{
for (int k=0; k<j; k++)
printf("*");
}
}