#include
using namespace std;
int main() {
int n;
cin>>n;
if(n>2 && n<1000000000){
if(n%2==0) {
int a=n/2;
int b=aa;
int ans1=b-1;
int ans2=b+1;
int x=ans2ans2;
int y=nn;
int z=ans1ans1;
if(x==(y+z)){
cout<<ans1<<" "<<ans2;
}
else{
cout<<"-1";
}
}
else {
float a=nn;
float p=a/2;
float ans1=p-.5;
float ans2=p+.5;
int x=ans2ans2;
int y=nn;
int z=ans1ans1;
if(x==(y+z)){
cout<<ans1<<" “<<ans2;
}
else{
cout<<”-1";
}
}
}
else{
cout<<"-1";
}
return 0;
}
Hello @Abhishek4799,
Please, read the constraints carefully.
N <= 10^9
So, the product of such larger numbers will be larger than the range of int.
Solution:
Make all the data types as long long int.
Let me know if you still face any issue.
Hope, this would help.
Give a like if you are satisfied.
its still not working . I also tried to remove the decimal integers but still some cases are wrong
Here’s the code #include using namespace std; int main() { long double k; cin>>k; long long int n=k; if(k-n==0){ if(n>2 && n<1000000000){ if(n%2==0) { long long int a=n/2; long long int b=aa; long long int ans1=b-1; long long int ans2=b+1; long long int x=ans2ans2; long long int y=nn; long long int z=ans1ans1; if(x==(y+z)){ cout<<ans1<<" “<<ans2; } else{ cout<<”-1"; } } else { long double a=nn; long double p=a/2; long double ans1=p-.5; long double ans2=p+.5; long long int x=ans2ans2; long long int y=nn; long long int z=ans1ans1; if(x==(y+z)){ cout<<ans1<<" “<<ans2; } else{ cout<<”-1"; } } } } else{ cout<<"-1"; } return 0; }
Hello @Abhishek4799,
Share your code using Online Coding Blocks IDE.
The way you have shared it may introduce many syntax errors to it.
STEPS:
I’ll correct it for you. 
Sorry! for the late reply
Hey @Abhishek4799,
I have corrected your code:
Refer to the comments for better understanding.
Hope, this would help.
Thank you so much !