Sir,please expain the problem "playing eith bits"

#1

i am not able to understand the output.how 10 and 15 gives 17 set bits

#2

hello @Abhishmu5
i think question is not clear to u.
the question is asking u to count the total set bits in numbers ranging from a to b.

for example if a=2 and b= 5
then numbers in this range will be 2, 3 ,4. 5
now we need to calculate number of set bits in each of these numbers and take their sum.

2 -> 10 (binary) ( 1 set bit)
3 -> 11 (binary) ( 2 set bit)
4 -> 100 (binary) ( 1 set bit)
2 -> 101 (binary) ( 2 set bit)
now take sum of all set bits i.e 1 + 2 + 1 + 2
so our answer will be 6.

#3

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