Sir, not showing either code is correct or not

#1

Compilation result is also coming
#include
using namespace std;

int main() {
int n,temp,rem,sum;
cin >> n;
temp =n;
while(n>0){
rem = n%10;
sum = sum + (rem * rem * rem);
n = n / 10;
}
if ( sum == temp)
cout << “true” << endl;
else cout << “false” << endl;

return 0;

}

#2

@naveengandhinow your code will only works for 3 digit number,Armstrong number is where you have to calculate sum of power(rem,no_of_digit_in_n) but your are taking only power of 3.

#3

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