Simple input third test case

#1

code passes third test case if i write
sum>=0
and fails when sum>0
why this happens

#2

Hey Pratik, can you share your code, so that we can help you with the exact issue in the code.

#3

https://ide.codingblocks.com/s/48162

#4

Heyy Pratik , i think you shared the wrong code . Can you share the code for this particular question ?

#5

#include
using namespace std ;
int main() {
int i, sum=0;
while(1){

cin>>i;
sum=sum+i;
 
if(sum>=0) {cout<<i<<endl;}
 
else {break;}

}
return 0;

}

#6

Yeah ! It’s obvious that sum>=0 should get accepted because its mentioned in the question that you have to print the input until the cummulative sum becomes negative i.e you have to print n till sum>=0 .
Is it clear now ?

#7

I want to know why third test case fails for sum>0 but pass if sum>=0

#8

because it is given that you have to stop processing when sum becomes negative only and when sum>=0 that means sum is not negative if sum > 0 or sum=0

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