Simple input in fundamental challenges

#1

how to take inputs? the question says take a list of numbers , is this to be predefined

#include
using namespace std;

int main()
{
int a[]={1,2,88,-100,49};
int sum=0;
int i=0;

int s=sizeof(a)/sizeof(a[0]);

while (i<s)
{
    sum=sum+a[i];
    if(sum>=0)
    {
        cout<<a[i]<<endl;
        i++;
    }
    else
    {
        break;
    }
}

}

this is my take on the question, but on submitting no test case pass

#2

Hi Ashish,
In this question you have to maintain a sum variable and take inputs and print them until the sum becomes negetive and donor print that input on which it become negetive.

#3

Hey Ashish, there will be no predefined list which means you will never know number of element in the list.

Small hint: while(cin>>arr[i]) to take inputs, don’t forget to increment the value of i inside the while loop

#4

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#5

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