Sanketandstrings!

#1

my code and wrong output

#2

Hello @suraj20000421,

The problem is with the input string s. I would suggest you to print s to understand this.
getline(cin,s);
cout<<s<<endl;

Observation:
The input for s is a null string(""), for all testcases.

Solution:
cin>>k;
cin.ignore(); //This is the solution to your problem.
getline(cin,s);
// cin.ignore() is a predefined function which ignores/clears one or more characters from the input buffer.

Explanation:
When you read anything from the standard input device, it firstly goes into the input buffer.
The input buffer is a location that holds all incoming information before it continues to the CPU for processing.
So, when compiler will take the value of k using cin statement. It will automatically insert a ‘\n’ at the end. After reading the value of k from the buffer, ‘\n’ will still remain in the buffer.
cin.getline() treats ‘\n’ as a delimiter.
Thus, it will read ‘\n’ present in the buffer and would terminate, storing an empty string in s.
By using cin.ignore(), you can ignore the ‘\n’ present in the buffer.

Hope, this would help.
Give a like, if you are satisfied.

#3

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