Run time error on test cases

#1

#include<bits/stdc++.h>
using namespace std;

int ansdp(int n){
if(n==0){
return 1;
}

int a[n];
int b[n];
a[0] = b[0] = 1;

for(int i=1;i<n;i++){

  a[i] = b[i-1];
  b[i] = b[i-1] +a[i-1];

}

return a[n-1] + b[n-1];

}

int main() {
int t;
cin>>t;
for(int i=0;i<t;i++){
int n;
cin>>n;
return ansdp(n);
}
}

here a[i] represents all strings ending with 1 and b[i] represents all strings ending with 0.

#2

Hi @Mohitpandey29
in ur int function instead of using “return ansdp(n)”,
use cout<<ansdp(n)<<endl since once u use return statement in main() function, the int main() function is exited and ur code terminates but since value of t>1, it gives run time error. so try not to use return ansdp(n) in main and try using cout<<ansdp(n)<<endl.

Hope dis resolves ur doubt.

#3

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