Robot Collect Points

#1

please provide some hints .
my approach :
calling recursion on three cells.

#2

Replied on other same thread by you

#3

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#4

please provide some hints . my approach : calling recursion on three cells.

#5

@RAHUL
Intuitively, start from every cell and try to build a word in the dictionary. Backtracking (dfs) is the powerful way to exhaust every possible ways. Apparently, we need to do pruning when current character is not in any word.

steps:
1.make trie for the input string array
class TrieNode {
TrieNode[] next = new TrieNode[26];
String word;
}
2. start from 0,0 to m,m
do a dfs travesal from each i,j cell
3. in dfs function update the current character to # so that the current character cannot be used again
a. check for all 4 positiion i-1, j || i+1, j || i,j+1 || j,j-1
b. remember to backtrack the position

i hope this explains how u would go about the problem

1 Like
#6

thanks rated 5 stars.