Revising quadratic equation not resolved by mistake it clicked

#1

import java.util.Scanner;
public class Main {
public static void main(String args[]) {
Scanner scn=new Scanner(System.in);
int a=scn.nextInt();
int b=scn.nextInt();
int c=scn.nextInt();
int x,y;
if(((bb)-(4a*c))>0)

     {  x=((-b)+((b*b)-(4*a*c)))/(2*a);
         y=((-b)-((b*b)-(4*a*c)))/(2*a);
         System.out.println("roots are real and distinct");
         
         System.out.print(x +" ");
         System.out.println(   y);
     }  
       else if(((b*b)-(4*a*c))>=0)
       { System.out.println("roots are real and equal");
        x=(-b)/(2*a);
        y=(-b)/(2*a);
         System.out.print(x +" ");
          System.out.println(y);
       } 
        else
        { System.out.println("roots are imaginary");
          System.out.println("complex roots");
        }




    

}

}

#2

how to find square root of number

#3

how to find squareroot of number using logic

#4

Use inbuilt Math.sqrt();
if it helps please mark the doubt as resolved.

#5

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