#include
#include
using namespace std;
void work(string &s,string &o,int n,int i)
{
if(i==n)
return;
if(s[i]==s[i+1])
return work(s,o,n,i+1);
else
o+=s[i];
}
int main()
{
string s;
cin>>s;
string o="";
int n=s.length();
work(s,o,n,0);
cout<<o<<endl;
return 0;
}
whats wrong in code…?
@ynikhil1999 hey nikhil there is no such need to take new string for output you can output you input string
just pass your input string in function and i+1 n and in function remove else part do cout<<s[i];
and make a call after printing work(s,i+1,n)
and above do return s,i+1,n when s[i]==s[i+1]
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