Regarding pass by reference in insertion in linked list

#1

in the function InsertAtHead(node* &head,int d)
we do node* temp=head. why didn’t we do node* temp = *head as we do in other cases in pass by reference??

#2

Hello @apurvaraina99,

As the head is itself a pointer variable pointing the first node of the linked list i.e. contains the address of the first node of the linked list.

when you write:
node* temp=head;
you are creating a pointer variable(temp) of type node and assigning the value stored in head i.e. the address of the first node of the linked list.

and by writing:
node* temp = *head;
you are assigning the value stored at the address stored in head variable, which might give an error.

Hope, this would help.
Give a like if you are satisfied.

#3

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