In the video, the instructor said that we can do the following:
int *a = new int[10];
Then we can reallocate the memory by doing something like
a = new char[30];
But won’t it end up changing the type such that when earlier:
a+1 would have been array[1]; for the integer array
But given that in the next case it point to a char then won’t it point to array[5] or something as int is 4bytes and it will skip 4bytes?
Reallocation of the dynamic memory
@varun.saxena this is an unvalid reallocation as a is already declared as pointer referencing for integer values, hence it cannot be used to reallocate to char type!
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