Rain Water Harvesting(FANG)

#1

I can’t understand the best way approach. can you please elaborate what exactly are we doing in that

#2

Hey @Maazkhan An element of the array can store water if there are higher bars on left and right. We can find the amount of water to be stored in every element by finding the heights of bars on left and right sides. The idea is to compute the amount of water that can be stored in every element of array. For example, consider the array {3, 0, 0, 2, 0, 4}, we can store three units of water at indexes 1 and 2, and one unit of water at index 3, and three units of water at index 4.

A Simple Solution is to traverse every array element and find the highest bars on left and right sides. Take the smaller of two heights. The difference between the smaller height and height of the current element is the amount of water that can be stored in this array element. Time complexity of this solution is O(n2).
If you still didn’t get it you can ask me :slight_smile:

#3

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