Problem with string copy

#1

why strcpy runs with case 2. but not with case 1 ? bith have same type of arguments…

#2

@gaurav19063,
strcpy(), takes char* as argument not string.

#3

but have a look at the code it is taking string as an argument

#4

@gaurav19063,

  1. is taking a string as parameter, and that is why giving compilation error
  2. is taking char* as parameter, and that is why working perfectly (Yes, “hello” is a char array not string)
#5

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#6

strcpy(a,“hello”) ;// 2.
But it is a string not a character array.

#7

@gaurav19063,
Why do you think so…??

#8

it is written in chords thats why…

#9

@gaurav19063,
Written in chords means character array implicitly.

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