Problem in Slicing

#1

Why output is ’ ’ not ‘o’
in below image?

#2

41%20PM
41%20PM1599×899 192 KB

#3

In Line 26…

#4

First comes the starting index and than after colon comes the ending index.
For your example:
-1 index will refer to 4 index
-3 index will refer to 2 index.

So your code in line 26 is similar to writing a[4:2] and that’s the reason ‘’ comes as output.
If you want to print ‘o’ use a[-1:] which means print all characters after last character i.e. ‘o’

Hope this cleared your doubt. :blush:

#5

So it should cause an error ?

#6

No, no error will be caused but it will not give any output.

#7

As 4 is starting index and it is included so it should atleast print ‘o’?

#8

No because it has to start from index 4 and go uptill index 1(i.e. 2-1, or ending_index-1), but there is no pathway possible, and it does not print anything. This is not like something, that it should print atleast first character, its like print if complete path is possible else do not print anything.

#9

thanks… doubt resolved.

#10

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