For the first testcase ,
The total cost of rickshaws = min( min(2 * 1, 3) + min(5 * 1, 3), 7) = min(5, 7) = 5
The total cost of cabs = min( min(4 * 1, 3) + min(4 * 1, 3) + min(4 * 1, 3) , 7) = min ( 9, 7) = 7
Total final cost = min( totalCabCost + totalRickshawCost , c4) = min( 5 + 7, 19) = min ( 12, 19) = 12
We print 12.
