since question is not understood by me please provide another testcase.
please check my submitted code.
Please provide me another testcase
SAMPLE TESTCASE :
Initially:
A= [3, 4, 7, 6, 5]<-TOP
After 1 iteration:
A1= [6, 4]<-TOP
B1= [5, 7, 3]<-TOP
We should output numbers in B1 first from top to bottom, and then output numbers in A1 from top to bottom.
Sample Input 1
5 2 3 3 4 4 9
Sample Output 1
Explanation 1
Initially:
A0= [3, 3, 4, 4, 9]<-TOP
After 1st iteration:
A0= []<-TOP
A1= [4, 4]<-TOP
B1= [3, 3, 9]<-TOP
After 2nd iteration:
A1= []<-TOP
B1= [4, 4]<- TOP
B2= [3, 3, 9]<-TOP
We should output numbers in B1 first from top to bottom, and then output numbers in B2 from top to bottom.
4 4 9 3 3
what’s wrong in my code. actually you printed alter first b1 have to print then a2(means 1st divisible stack then non didvisble stack)
i think you don’t understand problem completely
please check you code again
approach
first you have to make q iteration
in each iteration first calculate ith prime no
and then check which nos from stack A are divisible with this ithprime no, which are divisible put them into stack B and which are not put them into stack temp and after that again pour it into stack A
i think you don’t understand problem completely
please check your code again
you can use this code as refrence
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