Please explain the test cases

#1

please explain the test cases

#2

@sharad1103
Sample Input
2
(((a+(b))+(c+d)))
((a+(b))+(c+d))

Sample Output
Duplicate
Not Duplicates

You just have to check here that if there are unnecessary parenthesis or not.
In the 1st case (((a+(b))+(c+d))) you can observe that the first parenthesis pair is not necessary(this expression could be represented by ((a+(b))+(c+d)) ) hence you have to print Duplicate.
In case 2 there is no unnecessary parenthesis so you print Not Duplicates
This problem is somewhat similar to the valid parenthesis problem using stack. Try to think out of a logic.

#3

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