Please explain the meaning of this line?

#1

After Q iterations, cards can only be on pile B1, B2, B3, . . . BQ, AQ .

#2

Hello,
Let’s understand this with the help of an example.

INPUT:
N=5
Q=2
A(0)th stack : 1 2 3 4 5

Processing:
iterate for i =1 to Q;

for i=1(frst iteration):

  1. Pop top element of A(i-1)th (A(0)th) stack i.e. 5
  2. Check, ((top_element i.e. 5)%(ith prime number i.e. 1st prime number, 2)) == 0 ? Push top_element to B(i) i.e. B(1)th stack : Push top_element to A(i)i.e.A(1)th stack;

After repeating the same for all elements of stack A(0):
A(0)=[] i.e. empty as all elements have been popped.
A(1)=[5,3,1] as they are not divisible by 2.
B(1)=[4,2] as they are divisible by 2.

for i=2=Q (second and last iteration):

  1. Pop top element of A(i-1)th (A(1)th) stack i.e. 1
  2. Check, ((top_element i.e. 1)%(ith prime number i.e. 2nd prime number, 3)) == 0 ? Push top_element to B(i) i.e. B(2)th stack : Push top_element to A(i)i.e.A(2)th stack;

After repeating the same for all elements of stack A(1):
A(1)=[] i.e. empty as all elements have been popped.
A(2)=[1,5] as they are not divisible by 3.
B(2)=[3] as they are divisible by 3.

Output:
print elements of B(1),B(2),A(2)

2
4
3
5
1

Note: top element of the stack is popped first.

Hope, this would help.
Give a like if you are satisfied.

#3

can you please tell the problem in my code i am using DEQUE

#4
#5

But, what is need of DEQUE?
i’ll soon reply to your query after examining your code.

#6

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