Please explain output

#1
#2

as int is of 4 byte and char is of 1 byte and u explicity convert b into char * and refer to a char pointer
so if u do x[0] then it will add on the last bit
for more understanding
do
int *p=&b
p[0]=2
output will be 2
as the pointer is of same type so it change the
whole but char is of only 1 byte so it will change only 1 byte portion u can say

hope this help

#3

please explain this conept on this ques how we got the ans

#4

as pointer has the address of variable so char pointer only have the address of last bit of the integer u r pointing explicitly so x[0] means only change the last bit as x is pointing to that memory only
x[1] has no relevencre