Pigeon hole code

#1

In the code, he didnt check if freq array element is greater than equal to 2 or not

#2

@rohitgarg025 we are using nC2 formula, ie n(n-1)/2
n >= 0 here
if n == 0, then expression is 0*(-1)/2 = 0
if n == 1, then expression is 1*0/2 = 0

so there is no need to check

#3

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