Pattern double sided arrow

#1

please share me the logic for this code and explain me please

#2

please reply me fast

#3

hey @tarshid7 check this


If have any issue in understanding let me know, will help accordingly.

#4

please explain me the logic

#5

please explain me the full code logic

#6

try to understand once, it’s simple. i am explaining it for input 7,
run a for loop for 7 times, and print space then 1, so that you get

            1

then you have to run a for loop for n/2 +1 time that is 4, and each time you have to decrease the number of space by 1, then print number in reverse order like

        2 1

after printing that print number in ascending order

        2 1   1 2

do this n/2 times , then your upper part will be like this

            1
        2 1   1 2 
    3 2 1       1 2 3 
4 3 2 1           1 2 3 4

do the same thing in reverse order for next half

#7

at last if(n!=1) without it also we can just cout<<1 Is it possible just check it once

#8

is it necessary then please explain me why

#9

Last line ka 1 bhi toh print krwana hai na? Agar n 1 ke equal hai toh last line wala 1 already print ho jayega, pr agar ni toh hum explicitly print kr rhe hai. Just a check.

#10

without that also we can print it just check it once exclude it and run it once

#11

check for input n = 1, you will get it.

#12

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