#include
using namespace std;
int main () {
int c=0,r=2,k,n3=1,n;
cin>>n;
for(int i=0;i<=n;i++)
{
for(int j=0;j<i;j++)
{
cout<<"1 ";c++;
if(c%7==0)
{ j+=n3;
for( k=0;k<r;k++)
cout<<"0 ";j++;
r*=2;n3+=1;
}
}
cout<<endl;
}
return 0;
}
@parastandon4 Your logic is going wrong.
The logic is simple. When the column position is 0 ie. j==0 and also when j==i (ie. the diagonal element) you will always have to print 1.
In other Cases when j!=0 , you will have to check if i%2==0(ie. even positioned row) . If it is an even positioned row, you will have to print 1, else print 0.
When input is 6:
1 ----> since j==0
11 —> since j==0, j==i
111 —> since j==0, i%2==0, j==i
1001 —> since j==0, i%2!=0, i%2!=0, j==i
11111
100001
and so on.
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