#include
using namespace std;
void pythogtriplet(long long int n){
if(n==1||n==2){
cout<<’-1’;
}
else if(n%2==0){
long long int var = n * n / 4;
cout<<var - 1<<" “<< var + 1;
}
else if(n%2!=0){
long long int var = n * n +1;
cout<<var/2 - 1<<” "<<var/2;
}
}
int main() {
long long int n;
cin>>n;
if(n>2){
pythogtriplet(n);
}
else{
cout<<’-1’;
}
return 0;
}
hey @Bond007 your answer is wrong for cases when n is odd, If n is odd the two solutions are (nn - 1)/2 and
(nn + 1)/2. here is your code after rectifications
no bro , for n also the condition what i have written is correct. the thing is i am printing string ‘-1’ instead of -1. any ways thank you for the reply
@Bond007, it is possible that what i am suggesting might be simplification of what you’d written, i am sorry for misinforming you.
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