On what condition does the program terminate?

#1

string s = “bca”;

do {
cout << s << ’ ';
} while(next_permutation(s.begin(), s.end()));

cout << s;

I figured out the output of the program but I am not able to understand how it terminates.

#2

hello @ritkumar

if next larger permuatation doesnt exist then in that case ,next permuation will return false and ur while loop will stop .

#3

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