Odd even code doubt

#1

I feel like I am dont everything right with my code or maybe I dont understand the problem. It says that if no is odd then the sum should be divisible by 4 and if the no. is even then it should be divisible by 3. right? Is there anything that I am missing

#2

it is mentioned that if the sum of digits which are even is divisible by 4 or sum of digits which are odd in that number is divisible by 3. which means you need to maintain 2 sum odd_sum and even_sum and add even digits in even_sum, odd digits in odd_sum and check the condition
Code

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#3

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#4

can you tell me what is wrong in this code
#include

using namespace std;

int main()

{

int k,o=0,e=0,n,no,i,p,q;

cin>>p;

if(p>=0 && p<=1000)

{n=p;}

for(i=0;i<n;i++)

{cin>>q;

if(q<=1000000000 && q>=0)

{no=q;}

while(no!=0)

{

k=(no%10);

no=no/10;

if(k%2==0)

{e=e+k;}

else{o=o+k;}

}

if(e%4==0 || o%3==0)

{cout<<“YES”;}

else{cout<<“NO”;

}

e=0;

o=0;

cout<<"\n";}

return 0;

}