Odd even back in delhi

#1


sir output is correct, but does not passes tests.

#2

hi @ritikbunty2511_729d0258992e0982, u need to find the sum of even digits in the no (say SUM1) and sum of odd digits in the no (say SUM2)
then if SUM1 is div by 4 or SUM2 is div by 3 you can print yes

eg : 1235
SUM1 = 2; --> not div by 4 (failed)
SUM2 = 1 + 3 + 5 --> 9 --> div by 3 (passed)

any one passes print yes

u can refer the the code if having difficulties in implementation https://ide.codingblocks.com/s/657615