Odd block in this manmohan loves problem

#1

i don,t get odd row code in this problem plz elaborate it

#2

Hey @rakesh800650
For the odd row, you’ve to print as many 1s as is the serial number of the row
The inner code of the odd row part is:

int col = 1;
if(row%2!=0){
while(col <= row){
cout << 1;
col++;
}
}

so for the odd rows, this prints 1 row no. of times, where col is the counter that goes from 1 to row.

#3

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