Not accepting the program

#1

Dear sir;
it is not accepting.
please check and debug my code.
#include
using namespace std;
int main(){

int n;
cin >> n;

if(n>=0 & n<=1000){
long long int a[1000];
for(int i=0;i<n;i++){
    cin >> a[i];
}

int b[1000];
for(int i=0;i<n;i++){
    int r,temp;
    temp = a[i];

    int sum  = 0;

    while(temp > 0){
        r = temp%10;
        sum += r;
        temp /= 10;
    }
  b[i] = sum;
}

for(int i=0;i<n;i++){
    if(b[i]%2 == 0 & b[i]%4 == 0){
        cout << b[i] <<" Yes" << endl;

    }
    else if(b[i]%2 != 0 &  b[i]%3 == 0){
        cout << b[i] <<" Yes" << endl;

    }
    else{
        cout <<  b[i] <<" No" << endl;
	 }

}

}
else{
cout << " ‘n’ not in range" << endl;
}

return 0;
}

#2

hey Saikat!, for a given number you have to calculate sum of digits of even and odd numbers separately and output yes if sum_of_evens%4==0 or sum_of_odds%3==0,else output NO.
for this maintain two variables - sum_of_evens and sum_of_odds.
Please rewrite code again as this code is far from correct solution

#3

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