Next permutation

#1

syntax of next_permutation()

#2

@janmejai20singh hey ,here is syntax:
bool next_permutation (BidirectionalIterator first,
BidirectionalIterator last);
Parameters:
first, last : Bidirectional iterators to the initial
and final positions of the sequence. The range
used is [first, last), which contains all the elements
between first and last, including the element pointed
by first but not the element pointed by last.

return value:
true : if the function could rearrange
the object as a lexicographicaly greater permutation.
Otherwise, the function returns false to indicate that
the arrangementis not greater than the previous,
but the lowest possible (sorted in ascending order).
eg.
#include <algorithm>

#include <iostream>

using namespace std;

int main()

{

int arr[] = { 1, 2, 3 };

sort(arr, arr + 3);

cout << "The 3! possible permutations with 3 elements:\n" ;

do {

cout << arr[0] << " " << arr[1] << " " << arr[2] << "\n" ;

} while (next_permutation(arr, arr + 3));

cout << "After loop: " << arr[0] << ' '

<< arr[1] << ' ' << arr[2] << '\n' ;

return 0;

}
The 3! possible permutations with 3 elements:
1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
After loop: 1 2 3

#3

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