Mixtures problem

#1

please explain me the concept by providing a dry run for the second test case in the video

#2

arr[] -> 40, 60, 20.

  1. first option is to break at i=0.
    so subproblems are (40) and (60, 20) so here if you will furthur break (60, 20)
    then (60) and (20) since for i>=j return 0, so they return 0
    now for (60, 20) the answer is 60*20 = 1200
    which will be returned to (40, 60, 20) here we know the answer for (40) and (60, 20) subproblems
    so here answer will be = answer_for(40) + answer_for(60, 20) + 40 * (60+20)
    = 0 + 1200 + 3200 = 4400

  2. similarly if break i=1 => (40, 60) and (20)
    so here = answer_for(40, 60) + answer_for(20) + (60+40)%100 * (20).
    = 2400 + 0 + 0 = 2400

@aslesha.j7 i hope this clears your doubt

#3

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