Manmohan loves patterns

#1

Please Please tell me why this code is not passing the testcases given in problem manmohan loves patters-II

import java.util.*;
public class main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = 5;
System.out.println(“1”);
for(int i=1;i<n;i++) {
System.out.print(i);
for(int j=0;j<i-1;j++) {
System.out.print(“0”);
}
System.out.print(i);
System.out.println();
}
}
}

#2

i dont know how the indentation changed automatically. Apologies.

#3

Hii Mudit,
First you don’t have to fix value of n, you have to take the value of n from user. And in this question the correct logic is
If the row is equal to 1 then print 1
Else if column is 1 or column is equal to nst then print row - 1 , else print 0 where nst is the total no. of column in each row

#4

Hi Mudit, as you are not responding to this thread, I am marking your doubt as Resolved for now. Re-open it if required.

Please mark your doubts as resolved in your course’s “ Ask Doubt ” section, when your doubt is resolved.

#5

I didnt got the logic which you are telling me. I have changed the code and taken input from user and it started working fine. Can you please explain the logic and if possible please provide the code also.

#6

Hi Mudit,
See for input 5, output is:
1
11
202
3003
40004

when we start looking the pattern from row no. 2 then you can observe that first and last character in every row is row no. -1 and in between character are 0 and total no. of characters in each row equals to row number. And row no. 1 always contain 1.