ll denom=1ll;
what does this statement mean?
ll is long long, that’s ok.
But that ‘=1ll’, I didn’t understand that
Ll denom= 1ll; what is the meaning of this?
@SamyakJain3825 The LL makes the integer literal of type long long .
So 2LL , is a 2 of type long long .
Without the LL , the literal would only be of type int .
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